Question

please help me in this problem​

Answer 1

1 -diameter of 1 food piece =2.8
R = 2.8/2 = 1.4
circumference of semicircle = πr
22/7 ✖ 1.4 = 4.4cm
total distance covered by ant = 4.4+2.8=7.2cm

b part = diameter =2.8cm
r = d/2 = 2.8/2 = 1.4cm
circumference = πr
22/7 ✖ 1.4= 4.4cm
total distance = 4.4+1.5+2.8+1.5=10.2cm

c part= diameter = 2.8cm
r= d/2 = 2.8/2=1.4cm
circumference of semicirle= πr
22/7 ✖ 1.4= 4.4cm
total distance = 4.4+2+2=8.4cm

Hence in the food b the ant takes longer round = 10.2cm

Answer 2

a) r=d/2 = 2.8\2

= 1.4cm

circumference of circle= πr =22\7*1.4=4.4

total distance = 4.4+2.8= 7.2

b) r=d\2=2.8\2

=1.4cm

cir of circle = πr 22\7*1.4

=4.4

total distance =1.5+2.8+4.4=10.2

c)r=d\2=2.8\2=1.4

cir of cirle πr 22\7*1.4=4.4cm

td= 2+2+4.4=8.4

hence,b) is longer

i hope it will help u

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