Question

Please help me in this question ​

Answer 1

Answer:

ABC=ACB(angles opposite equal sides are equal)

DBC=DCB(Same reason)

Adding LHS and RHS

ABC+DBC=ACB+DCB

ABD=ACD

Hence proved

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Brainliest please?

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Answer 2

Answer:

In triangle ABC

In triangle ABC AB=BC

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDC

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DC

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DCTherefore,Angle DBC=Angle DCB(Angle opposite to equal side)-equation 2

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DCTherefore,Angle DBC=Angle DCB(Angle opposite to equal side)-equation 2on adding equation 1 and equation 2

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DCTherefore,Angle DBC=Angle DCB(Angle opposite to equal side)-equation 2on adding equation 1 and equation 2Angle ABC + Angle DBC = Angle ACB + Angle DCB

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DCTherefore,Angle DBC=Angle DCB(Angle opposite to equal side)-equation 2on adding equation 1 and equation 2Angle ABC + Angle DBC = Angle ACB + Angle DCBTHEREFORE,Angle ABD=Angle ACD

In triangle ABC AB=BCtherefore,Angle ABC=Angle ACB(Angle opposite to equal side are equal)-equation 1In triangle BDCBD=DCTherefore,Angle DBC=Angle DCB(Angle opposite to equal side)-equation 2on adding equation 1 and equation 2Angle ABC + Angle DBC = Angle ACB + Angle DCBTHEREFORE,Angle ABD=Angle ACD Hence proved..

I hope it will be helpful