Question

please help me in this question ​

Answer 1

Answer:

1.First draw the horizontal line BC=6cm(with the scale)

2.take out your compass keep it on the rule and measure 10cm

3.take any points(either B or C)as centre draw semicircle on upper half of the triangle..

4.take out the protractor and keeping B as the centre drop a point on exact 90 degree

5.draw the line AC and connect the hypotenuse..

AS the class work draw a rough figure on top and

write the steps..Hoping It Helps...

Answer 2

${\underline {\underline {\huge {\sf { Required \: Answer: } }}}}$

Given:

• ABC is a right angled triangle.

• BC = 6cm (Base)

• AC = 10cm (Hypotenuse)

To calculate:

• AB = ? (Perpendicular)

Calculation:

Applying Pythagoras property:

• ${\underline {\boxed {\huge {\sf {\pink { {H}^{2} = {B}^{2} + {P}^{2} } }}}}}$

$\sf { ⇢ {H}^{2} = {B}^{2} + {P}^{2} }$

⠀⠀⠀

$\sf { ⇢ {AC}^{2} = {BC}^{2} + {AB}^{2} }$

⠀⠀⠀

$\sf { ⇢{10}^{2} = {6}^{2} + {P}^{2} }$

⠀⠀⠀

$\sf { ⇢100= 36 + {P}^{2} }$

⠀⠀⠀

$\sf { ⇢{AB}^{2}= 100-36}$

⠀⠀⠀

$\sf { ⇢{AB}^{2} = 64 }$

⠀⠀⠀

$\sf { ⇢ AB = \sqrt{64} }$

⠀⠀⠀

$\boxed { \sf\pink { ⇢ AB = 8 cm}}$

Therefore,measure of AB is 8cm.

__________________________________