Question

please help me in this question

Answer 1

hope this helps you☺☺☺☺

Answer 2

Hey here is the solution
Let AB be the tower . Let C and D be the two points at distances a & b respectively from the base of the tower . Then ,AC=a and AD = b . Let angle ACB = θ and angle ADB = 90-θ .
Let h be the height of the tower AB.
In triangle CAB, We have
tanθ = AB/AC
tanθ = h/a ------->(1)
In triangle DAB , We have
tan(90-θ)=AB/AD
cotθ=h/b -------->(2)
From (1) & (2) we get
tanθ × cotθ = h²/ab
1= h²/ab
h²=ab
h=√ab metres
Hence Proved .
For diagram see the attachment