Question

please help me in this question

Answer 1

Given;- curved surface area of cone ;- πrl

LeT The radius be r1 and r2

According to question ;-

Given that one right circular cone is twice that of another circular cone.

⇒ (πr₁l₁)/(πr₂l₂) = 2/1

Case ll ;-

slant height of the second cone is twice that of first cone.

πr₁l₁)/(πr₂(2l₁)) = 2/1

⇒ (r₁)/(2r₂) = 2/1


⇒ (r₁)/(r₂) = 4/1

Ratios will be 4:1

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Answer 2

We know that curved surface area of the cone = πrl.

Let the radii be r₁ and r₂.

(i)

Given that one right circular cone is twice that of another circular cone.

⇒ (πr₁l₁)/(πr₂l₂) = 2/1

(ii)

Given that slant height of the second cone is twice that of first cone.

⇒ (πr₁l₁)/(πr₂(2l₁)) = 2/1

⇒ (r₁)/(2r₂) = 2/1

⇒ r₁ = 4r₂

⇒ (r₁)/(r₂) = 4/1

Therefore, the ratio is  4 : 1.

Hope it helps!