Question

please help me in this question
and describe it by give reason

Answer 1

angle Acb =60( by linear pair property)
angle abc =80 ( ba parallel to ce)
angle bac = 40 ( angle sum property)

Answer 2

$\huge{hey \: mate}$
$<b>$

Here is your answer > >

BA||CE

=>$\angle{A}$=$\angle{AEC}$=40°

$\angle{ACE}$+ $\angle{ECD}$+ $\angle{ACB}$=180°(Angles on a straight line)

40°+80°+ $\angle{ACB}$=180°

$\angle{ACB}$=60°

In Triangle ABC

$\angle{ACB}$+$\angle{CBA}$+ $\angle{BAC}$=180° (Angle sum property of triangle)

60°+ $\angle{CBA}$+40°=180°

$\angle{CBA}$=80°

Hope it helps!

Thankyou ☆ ☆