Question

Please help me in this question
find it's value​

Answer 1

Step-by-step explanation:

1/1-tan^2

1/1-( 1+sec^2)

1/sec^2

cos^2

Answer 2

Answer:

2sinθ × cosθ / 1 - 2sin²θ

Step-by-step explanation:

1 / 1-tanθ - 1 / 1+tanθ

= 1+tanθ - (1-tanθ) / 1 - tan²θ

= 2tanθ / 1 - tan²θ

= 2sinθ / cosθ / 1 - sin²θ / cos²θ

= 2sinθ / cosθ /  cos²θ - sin²θ / cos²θ

= 2sinθ / cosθ × cos²θ / cos²θ - sin²θ

= 2sinθcosθ / cos²θ  - sin²θ

= 2sinθcosθ / 1 - sin²θ - sin²θ

= 2sinθcosθ / 1 - 2sin²θ