Please help me in this question
find it's value
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Step-by-step explanation:
1/1-tan^2
1/1-( 1+sec^2)
1/sec^2
cos^2
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Answer:
2sinθ × cosθ / 1 - 2sin²θ
Step-by-step explanation:
1 / 1-tanθ - 1 / 1+tanθ
= 1+tanθ - (1-tanθ) / 1 - tan²θ
= 2tanθ / 1 - tan²θ
= 2sinθ / cosθ / 1 - sin²θ / cos²θ
= 2sinθ / cosθ / cos²θ - sin²θ / cos²θ
= 2sinθ / cosθ × cos²θ / cos²θ - sin²θ
= 2sinθcosθ / cos²θ - sin²θ
= 2sinθcosθ / 1 - sin²θ - sin²θ
= 2sinθcosθ / 1 - 2sin²θ
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