Please help me in this question
Question number 18
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- In triangle K M L and K N P
→ ∠K is common.
→ ∠KML = ∠KNP
So
- ΔKML ≅ ΔKNP
Then
KM/ML = KN/NP
(b+c)/a = c/x
So
x = (b+c)/ac
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Hope It helps u.
Thank u.
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