please help me in trouble
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Answered by
1
Answer:
7.5 cm
Step-by-step explanation:
Given:
PQ = 10 cm.
PO = 10 cm
PR = RQ = 16/2
= 8 cm
In ΔOPR
⇒ OR = √OP² - PR²
= √10² - 8²
= √100 - 64
= √36
= 6 cm
Let ∠POR be θ
In ΔPOR,
tanθ = PR/RO
= 8/6
= 4/3
We know OP ⊥ TP
In ΔOTP,
tanθ = OP/TP
4/3 = 10/TP
TP = (10 * 3)/4
TP = 30/4
TP = 7.5 cm
Therefore, Length of TP = 7.5 cm.
Hope it helps!
Answered by
0
Answer:
7.5 cm
Step-by-step explanation:
Given:
PQ = 10 cm.
PO = 10 cm
PR = RQ = 16/2
8 cm
In ΔOPR
⇒ OR = √OP² - PR²
√10² - 8²
√100 - 64
√36
6 cm
Let ∠POR be θ
In ΔPOR,
tanθ = PR/RO
8/6
4/3
We know OP ⊥ TP
In ΔOTP,
tanθ = OP/TP
4/3 = 10/TP
TP = (10 * 3)/4
TP = 30/4
TP = 7.5 cm
Therefore, Length of TP = 7.5 cm.
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