Question

please help me It is urgent ​

Answer 1

Answer:

$radius \: of \: two \: spheres \: are \: 2cm \: and \: \:4cm$

$volume \: of \: both \: spheres \: = sum \: of \: volume \: of \: both \: sphere \:$

$vol. \: of \: both \: spheres \: = \frac{4}{3}\pi {r1 }^{3} + \frac{4}{3} \pi {r2}^{3}$

$\: \: \: \: \: \: \: \: \: = \frac{4}{3} \pi( {r1}^{3} + {r2}^{3} )$

$\: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{3} \pi( {2}^{3} + {4}^{3} )$

$\: \: \: \: \: \: \: \: \: \: \: = 301.7 {cm}^{3}$

$the \: volume \: of \: cone \: and \: sum \: of \: both \: spheres \: are \: equal$

$height \: of \: cone \: = 8cm$

$\frac{1}{3} \pi l{r}^{2} = 301.7$

${r}^{2} = 301.7 \times 3 \div \pi \div l$

${r}^{2} = 301.7 \times 3 \times \frac{7}{22} \times \frac{1}{8}$

${r}^{2} = 36$

$r = \sqrt{36}$

$r = 6cm$

$the \: radius \: of \: cone \: is \: = 6cm$

plz thanks mate