Question

please help me it's really really important ​

Answer 1

Answer:

1

Step-by-step explanation:

[(x^a)^b]^2c÷x^(abc) = x^2abc÷x^abc

⇒x^(2abc-abc)  [∵x^m÷x^n=x^m-n]

=x^abc

=x^0 [∵abc =0]

=1

Answer 2

Hope this helps and is clear enough