Please, help me it's urgent.
FIND : ROOT (a^2+b^2)^2 - (a^2-b^2)^2
Answers
Answered by
0
Let (x+iy)2=4ab−2i(a2−b2)
Comparing the real and imaginary terms,
x2−y2=4ab----------------------------------------(i)
xy=a2−b2---------------------------------------(ii)
Comparing the magnitude,
x2+y2=4a4+4b4+8a2b2
⇒x2+y2=2a2+2b2 -(iii)
Solving (i) and (iii),
x2=a2+b2+2ab and y2=a2+b2−2ab
Hence,
x=a+b , y=a−b
or x=−(a+b) , y=b−a
Hence, option B is correct
Answered by
0
Let me give you a contradiction.
Let a=1a=1
and b=1b=1
Now, L.H.S. ,
a2+b2−−−−−−√=12+12−−−−−−√=2–√a2+b2=12+12=2
and R.H.S. ,
a+b=1+1=2a+b=1+1=2
Clearly,
2–√≠22≠2
Hence,
a2+b2−−−−−−√≠a+b
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