Math, asked by Anonymous, 1 month ago

PLEASE HELP ME IT'S URGENT

I need only correct answer
Wrong answer will be reported​

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Answered by Anonymous
4

Answer:

LHS

1/sin^2A-1/sin^2B

(sin^2B-sin^2A)/sin^2A*sin^2B

1-cos^2B-1+cos^2A/sin^2A*sin^2B

cos^2A-cos^2B/sin^2A*sin^2B

=RHS.

Hope it will help you.

Answered by Anonymous
1

Refer the attachment for solution

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