Question

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please find answer for 24)​

Answer 1

$\huge \sf \mathbb \color{Yellow}\underline{\colorbox{blue}{Answer \: 25:}}$

We know

(x+y+z)² =x² +y² +z²+2xy+2yz+2zx [Identity]

Here,

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

(2a+3b+4c)²

=(2a)²+(3b) ²+ (4c)² +2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

=4a² +9b²+16c² +12ab+24bc+16ca

Answer 2

Answer:

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