Math, asked by Anonymous, 9 months ago

please help me........

it's very urgent ..........

P alone can do 1/2 of a work in 6 days and Q alone can do 2/3 of the same work in 4 days . in how many days working together they finish 3/4 of the work.​

Answers

Answered by Anonymous
3

Answer:

Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9

They would take 9/2 days = 4 (1/2) days to complete the work working together.

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