Question

Please help me! Its maths question! I am doing my exam ​

Answer 1

1. 2 terms
2. [-a-(b+c)]
3. Like terms
4. m - 7p
5. 1.2345 × 10⁴ (not so sure though)
6. [(-3)²]³ = (-3)²ˣ³ = (-3)⁶  = 729
7. 21 -4 = 17
8. sum of the observations/number of observations

     9.(5x² - 3x  + 8)

     5x² - 8x + 5x +8    

x(5x-8) + 1(5x-8)

(x+1)(5x-8)

substituting,

(1+1)(5×1 - 8)

2(-3) = (-6)

      10. (a) y³

      11. 2(ab + bc + ca) from (-ab - bc - ca)

= (-ab - bc - ca) -[2(ab + bc + ca)]

= (-ab - bc - ca) - (2ab + 2bc + 2ca)

= -ab - bc - ca - 2ab - 2bc - 2ca

= -3ab - 3bc - 3ca = -3(ab + bc + ca)

   10. (b)

Factors = -6x²,y²,z and 1

    12. (a)we know that, a⁰ = 1

hence, 5⁰ × 25⁰ × 125⁰ = 1

(b)  (s×s×t×t×s×s×t) = s⁴ × t³

13. (5/3)³ × (4/7)³

we know that aⁿ × bⁿ = (a×b)ⁿ

(5/3×4/7)³ = (20/21)³

= 8000/9261

Hope it helps

have a great day