Question

please help me its urgent

Answer 1

HEYA......

We have for some number n

We know that;

43≡3modn43≡3modn

91≡3modn91≡3modn

183≡3modn183≡3modn

Here,

a≡bmodnmeans a-b is divisible by n exactlya≡bmodnmeans a-b is divisible by n exactly...

So we need to find the HCF of 40, 88, and 180

40=4×2×540=4×2×5

88=4×2×1188=4×2×11

180=4×9×5180=4×9×5

So the highest common factor and your answer is 4.

TYSM.....@GOZMIT

Answer 2

get deference of all it
183-91=92
183-43=48
91-43=48
now
HCF (48,92,140)
48=2×2×2×2×3
92=2×2×23
140=2×2×5×7
now get common in these no.
2×2=4
4 is the required answer.
I hope it's help u