Math, asked by SnehaSharma32, 1 year ago

please help me its urgent !!!!!!

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Answered by divergent07
0
(2/3) ^(2y-2) ×(2/3)^(y-6)=(2/3)^1
(2/3)^(2y-2+y-6)=(2/3)^1
so base same equate powers
3y-8=1
3y=9
y=3
answer......♥️♥️♥️
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