please help me last year.question
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Total integers is 98 ( excluding 1 & 100)
1)probability of divisible by 8 = 12/98 = 6/49
2)probability of not divisible by 8 = 1 - 6/49
= (49 - 6)/49
= 43/49
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1)probability of divisible by 8 = 12/98 = 6/49
2)probability of not divisible by 8 = 1 - 6/49
= (49 - 6)/49
= 43/49
The answer for ur question is given
Hope it helps u
Plssssssss mark me brainliest plss Plssssssss Plssssssss
FOLLOW me
saisagar6129:
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2,3,4..............99
Total outcome=98
(ⅰ)Number of outcome have divisible by 8=12
Probability of divisible by 8=12/98
=6/49
(ⅱ)Number of outcome have not divisible by 8=49-12=43
Probability of not divisible by 8=43/49
Total outcome=98
(ⅰ)Number of outcome have divisible by 8=12
Probability of divisible by 8=12/98
=6/49
(ⅱ)Number of outcome have not divisible by 8=49-12=43
Probability of not divisible by 8=43/49
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