Question

please help me... maths​

Answer 1

Answer:

Easy way is

sin A =√3/2 , A = 60

tan A = tan 60 =√3

cos B =√3/2 , B= 30

tan B = tan 30 =1/√3

Put values

$\frac{ \sqrt{3} - \frac{1}{ \sqrt{3} } }{1 + \sqrt{3} \times \frac{1}{ \sqrt{3} } } = \frac{1}{2} ( \frac{3 - 1}{ \sqrt{3}} ) = \frac{1}{ \sqrt{3} }$

Or directly it is formula of tan (A-B)

$\frac{ \tan(x) - \tan(y) }{ 1 + \tan(x) \tan(y) } = \tan(x - y) = \tan(60 - 30) = \tan(30) = \frac{1}{ \sqrt{3} }$

Answer 2

Answer:

Help chaya hai tho sir se pucho Naa idhar ak nakhare dikhna band karoo