Question

please help me maths class 8

Answer 1

Answer:

45 years

Step-by-step explanation:

Let the ages of two sons be x and y.

Then, the father's age = 3(x + y).

5 years hence:

∴ Age of sons = x + 5 + y + 5

                       = x + y + 10.

∴ Age of father = 3(x + y) + 5

                         = 3x + 3y + 5.

According to the given condition,

⇒ (3x + 3y + 5) = 2(x + y + 10)

⇒ 3x + 3y + 5 = 2x + 2y + 20

⇒ 3x + 3y + 5 - 2x - 2y - 20 = 0

⇒ x + y - 15 = 0

⇒ x + y = 15

Therefore:

Present age of the father = 3(x + y) = 45 years.

Hope this helps!

Answer 2

Answer:

The age of the father is 45.

Step-by-step explanation:

Solution:-

Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

3x+3y+5 = 2x+10+2y+10

3x+3y+5 = 2x+2y+20

3x-2x+3y-2y = 20–5

x+y = 15

Now the age of father was 3(x+y) → 3(15) → 45 (Putting the value of x+y)

Thus the age of the father is 45.