Question

please help me




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Answer 1

Answer:

the required answer is 100 m/s

GIVEN:

• acceleration, a= 10 m/s^2
• time , t= 10 s

TO FIND:

velocity, v

THREE EQUATIONS OF MOTION:

FIRST EQUATION:

V = u + at

SECOND EQUATION:

s = ut + (1/2)at^2

THIRD EQUATION:

V^2 - v^2 =2as

KEYS:

• v.......final velocity
• u...... initial velocity
• a..... acceleration
• t........time
• s...... displacement

SOLUTION:

since there is no information available regarding intial velocity, consider the initial velocity u = 0

apply first equation of motion,

$v = u + at \\ \\ v = 0 + (10)(10) \\ \\ v = 0 + 100 \\ \\ v = 100 \: m /s$

the increased velocity is 100 m/s.

ADDITIONAL:

in vertical motion ,the acceleration due to gravity comes into play.

in the three equations of motion , acceleration of the body will be replaced by acceleration due to gravity, g

Answer 2

$\sf{\underline{\boxed{\large{\blue{\mathsf{Correct\: Question}}}}}}$

• A bus has an acceleration of 10 m/s2 in a straight line. How much velocity is increased in 10 s?

_______________________

$\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• acceleration ( a ) = $\sf 10m/s^2$
• time ( t ) = 10sec
• initial velocity ( u ) = 0 m/s

_______________________

$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• final velocity ( v ) = ????

______________________

$\sf{\green{\underline{\underline{\bold{Solution}}}}}$

$\sf{\red{\boxed{\bold{\dag v = u + at }}}}$

$\implies v = 0 + 10\times 10$

$\implies v = 0 + 100$

$\implies v = 100m/s$

$\sf{\purple{\boxed{\bold{\dag final\: velocity \: = \: 100m/s }}}}$

______________________

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• velocity after 10sec is $\sf\dag 100m/s$