Question

please help me monday ko mera paper h​

Answer 1

Answer:

18 cm

Step-by-step explanation:

$r_{1}$= 2cm  $r_{2}$=12cm      $r_{3}$= 16cm

Spheres of radii $r_{1}$, $r_{2}$, $r_{3}$   are melted into a sphere of radius r.

$\frac{4}{3}$ π $r^{3}_{1}$ +$\frac{4}{3}$ π $r^{3}_{2}$ + $\frac{4}{3}$ π $r^{3}_{3}$  = $\frac{4}{3}$ π $r^{3}$

$r^{3}$ =  $r^{3}_{1}$ + $r^{3}_{2}$ + $r^{3}_{3}$  

$r^{3}$ = $2^{3}$ + $12^{3}$ + $16^{3}$

r = 18  

Answer 2

Answer:

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Answer

Open in answr app

(i) To verify : A×(B∩C)=(A×B)∩(A×C)

We have B∩C={1,2,3,4}∩{5,6}=ϕ

∴ L.H.S = A×(B∩C)=A×ϕ=ϕ

A×B={(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4)}

A×C={(1,5),(1,6),(2,5),(2,6)}

 ∴R.H.S.=(A×B)∩(A×C)=ϕ

∴L.H.S=R.H.S

Hence A×(B∩C)=(A×B)∩(A×C)

(ii) To verify: A×C is a subset of B×D

A×C={(1,5),(1,6),(2,5),(2,6)}

B×D={(1,5),(1,6),(1,7),(1,8),(2,5),(2,6),(2,7),(2,8),(3,5),(3,6),(3,7),

                  (3,8),(4,5),(4,6),(4,7),(4,8)}

We can observe that all the elements of set A×C are the elements of set B×D 

Therefore A×