Chemistry, asked by Anonymous, 1 month ago

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Answered by sai172982
17

Answer:

1) Na - 1s²2s²2p6 3s¹-k

2)P-1s²2s²2p6 3s²3p³-N

3) S-1s²2s²2p6 3s²3p⁴-O

4) F-1s²2s²2p5-Cl

Answered by allysia
7

Configurations (did it in 2 ways):

1. Shell wise:

(Old one, not very useful)

  • Sodium - 2,8,1
  • Phosphorous - 2, 8, 5
  • Sulphur - 2, 8, 6
  • Flourine - 2, 7

2. Orbital wise:

(This one help understand the bond and properties better.)

  • Sodium : 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2}

  • Phosphorous :  1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2} 3 {p}^{3}
  • Sulphur: 1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2} 3 {p}^{4}
  • Flourine : 1 {s}^{2} 2 {s}^{2} 2 {p}^{5}

Element in same group:

  • K
  • N
  • O
  • Cl

Explanation:

  • She wise electron filling each shell takes place as per the rule of 2 {n}^{2} where n is the number of shell.
  • While filling orbitals Hund's rule, Afbau's principle and pauli's principle must be kept in mind.
  • Element belonging to same group have same number of electrons in valency (last) shell.
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