Question

Please help me ↓

one side of the rectangular field is 4 metres and its diagonal is 5 metres what will be the area of the field​.

★Dont spam
★Spammers stay away from brainly
​

Answer 1

Given:-

• one side = 4m
• diagonal=5m

To find:-

• Area of rectangle.

Solution:-

By using Pythagoras theorem other side of rectangle can be determined.

$\large \mathtt{{5}^{2} = {x}^{2} + {4}^{2} }$

From here

$\large \mathtt{{5}^{2} - {4}^{2} = {x}^{2} }$

$\large \mathtt{25 - 16 = {x}^{2} }$

$\large \mathtt{9 = {x}^{2} }$

$\large \mathtt{ \sqrt{9} = {x} }$

$\large \mathtt{ 3 = {x} }$

Now we have two sides of rectangle and area of rectangle is given by product of sides

hence

Area= 3 x 4= 12m²

Answer 2

Answer:

12m²

Step-by-step explanation:

5 2 - 42

= √ 9

=3 m

So The area of the rectangular field = 4 x 3

= 5 2 - 42

= √ 9

=3 m

So The area of the rectangular field = 4 x 3

= 12m²

Hope it helps..