Question

please help me out ​

Answer 1

Answer:

Explanation:

Oxidation number of V in V2O5 = 2x-10 = 0

2x = 10

x= +5

Since atomic number of V (Vanadium) = 23

therefore its electronic configuration is 1s²2s²2p⁶3s²3p⁶4s²3d³

Now electronic configuration of its ion will be

1s²2s²2p⁶3s²3p⁶4s⁰3d⁰