Math, asked by girl73890, 16 days ago

please help me out ​

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Answered by beautifulworld12
1

Answer:

3. Area of a circle = (22/7) × r²

Where r is the radius of the circle

here radius of circular garden is 14 cm

Area of circular garden = (22/7)×14×14

=616cm²

4.Area of parallelogram = Base × height

A.T.Q.

16=8 × height

height =2 cm

5. length of rectangle is 40m and breadth is 20m

perimeter of a rectangle =2( length + breadth)

=2(40+20)

2×60

120m

6. area of a square = (side)²

ATQ

121=side²

side = 11m

Hope it helps.

Answered by aishwaryahk97sl
0

Answer:

3) The area of the circular garden is 616 cm^{2}

4) The height of the parallelogram is 2 cm

5) The perimeter of the rectangle is 120 m

6) The side of the square is 11 m

Step-by-step explanation:

3) The area of the circle = πr^{2}

Here 'r' is the radius of the circle

Given r = 14 cm

Area = πr^{2}

=(\frac{22}{7} )14^{2}

The area of a circular garden with a radius of 14 cm is 616 cm^{2}

4) The area of the parallelogram = b × h

Here 'b' is the breadth and 'h' is the height

Given the area = 16 cm^{2} and b = 8 cm

h = \frac{area}{b}

  =\frac{16}{8}

The height of the parallelogram = 2 cm

5) The perimeter of the the rectangle = 2(l + b)

Given the lenght l = 40 and the breadth b = 20

Perimeter = 2(40 + 20) = 120 m

The perimeter of the rectangle is 120 m

6) The formula of the area of the square = a^{2}

Here a is the side of the square

Given the area of the square = 121 cm^{2}

 a^{2} = 121 cm^{2}

a = 11 cm

The side of the square = 11 m

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