❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️
please help me out..
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Acekiller:
difficult for me
hope it doesn't come in exam
yaar maths ka answers koi nahi deta.....☹️☹️
ruko try karta hu
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1
HEY ANSHU HERE IS YOUR ANSWER--
Sol: The circle touches the sides BC, CA, AB of the right triangle ABC at D, E and F respectively.
Assume BC = a, CA = b and AB = c
Then AE = AF and BD = BF, CE = CD .
OE = OD = OF = r.
Here OEDC is a square then CE = CD = r.i.e., b – r = AF,
a – r = BF or AB = c = AF + BF = b – r + a – r
∴ r = (a + b - c )/2
Sol: The circle touches the sides BC, CA, AB of the right triangle ABC at D, E and F respectively.
Assume BC = a, CA = b and AB = c
Then AE = AF and BD = BF, CE = CD .
OE = OD = OF = r.
Here OEDC is a square then CE = CD = r.i.e., b – r = AF,
a – r = BF or AB = c = AF + BF = b – r + a – r
∴ r = (a + b - c )/2
Answered by
3
see it looks hard but I some how crack it
the photo is attached
hope you get it
thanks for this challenging sum
mark as brainliest
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please mark as brainliest
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