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first -
in triangle ADC
DAC + ADC + ACD = 180
60 + C + 70 = 180
C = 180 - 130
C= 50
C IS EQUAL TO THEIR FAREST ANGLES SUM
ADC = BAD + ABD
50 = 30 + ABD
ABD = 20
THE IN TRIANGLE BDA
ABD + BAD + ADB = 180
20 + 30 + ADB = 180
ADB = 180 - 50
ADB = 130
SO a = 20
b = 130
and c = 50
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