Math, asked by priyanjalisingh123, 6 months ago

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Answered by prakash70663
0

Answer:

first -

in triangle ADC

DAC + ADC + ACD = 180

60 + C + 70 = 180

C = 180 - 130

C= 50

C IS EQUAL TO THEIR FAREST ANGLES SUM

ADC = BAD + ABD

50 = 30 + ABD

ABD = 20

THE IN TRIANGLE BDA

ABD + BAD + ADB = 180

20 + 30 + ADB = 180

ADB = 180 - 50

ADB = 130

SO a = 20

b = 130

and c = 50

Answered by raashieawatade25
0

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