Question

please help me out from q2 to q6

Answer 1

Q2.

$force = mass \times accelertion \\ \: \: \: \: \: \: \: \: \: \: \: \: = kg \times m {s}^{ - 2} \: \\ \: \: \: \: \: \: \: \: \: \: \: \: = mass \: length \: {time}^{ - 2}$

MLT^-2

So 4th option is correct

Q6.

diameter is 14cm therefore radius will be 7cm

Now finding distance

$distance = 2\pi r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \frac{22}{7} \times 7 \\ \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: =44 \: cm$

Displacement will be zero as it comes back to its original position

so option 4 is correct

hope it helps...

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