Question

please help me out from this question ​

Answer 1

Answer:

Step-by-step explanation:

The ΔA
′
BC
′
whose sides are
4
3
​
of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60
∘


Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B
1
​
,B
2
​
,B
3
​
,B
4
​
on line segment BX.

Step 4: Join B
4
​
C and draw a line through B
3
​
, parallel to B
4
​
C intersecting BC at C
′
.

Step 5: Draw a line through C
′
parallel to AC intersecting AB at A
′
.

The triangle A
′
BC
′
is the required triangle.