Question

Please help me out guys!!! The picture is given.

Answer 1

Answer:

it seems difficult due to tedious calculations but it is easy enough to be solved

Step-by-step explanation:

#answerwithquality

#BAL

Answer 2

X1/X2+x+3/X-4 = 10/3

(x*2- 5x +4 +x^2-5x+ 5)/x-2)(x-4)= 10/3

(2x^2- 10x +10)/(x^2-6x+8)= 10/3

2(x^2-5x +5)/(x^2-6x+8) = 10/3

Dividing both sides by 2 we get

x 2. 5x +5)/(x^2-6x+8) = 5/3

By applying componendo and dividendo

(x*2- 5x +5+x^2-6x+8)/(x^2- 5x +5-x*2+6x-

B)=5+3/5-3

(2x^2-11x+13)/(x-3)=8/4

2x^2-11x+13=4(x-3)

2x^2-11X+13=4x 12

2x^2-15x+25-0

2x^2 - 10x-5x +25=0

2x{X-5)-5[x-5)=0

So, x=5/2,5

Reject 5/2 and we get

X = 5

Hope this will help