Question

please help me out guys with ch 3 linear equations in 2 variables continuation​

Answer 1

Answer:

given 13 x + ky = k... (1)

39 x + 6ky +4 ....(2 )

Step-by-step explanation:

first equation multiplied by 3

39x + 3ky = 3k ...(3 )

and subtract 2 from 3

1. 39 x + 3ky - 3k - 39 x - 6ky -4 = 0
2. 0x -3ky - 3k -4 = 0
3. -3 k(y - 1 ) = 4
4. k = -4/3 (y - 1)