Please help me out, I am having difficulty in this question. First and right answer with proper explanation would be surely marked as brainliest.
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In AOB ,BOC
AB=BC (Data)
OB=OB (Common)
<ABO=<CBO (Data)
therefore, AOB congruent to BOC (Side-Angle- Side)
<AOB = <BOC (In congruent triangles, corresponding elements are equal)
<ABO=<CBO
<AOB = <BOC
<ABO+<AOB =<CBO+<BOC
<ABO+<AOB=<DAB (In triangle, sum of two interior opposite angle equal to exterior angle)
<CBO+<BOC=< ECB(In triangle, sum of two interior opposite angle equal to exterior angle)
Therefore,
<DAB=<ECB
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