Question

Please help me out, I am having difficulty in this question. First and right answer with proper explanation would be surely marked as brainliest.

Answer 1

Answer:

In AOB ,BOC

AB=BC (Data)

OB=OB (Common)

<ABO=<CBO (Data)

therefore, AOB congruent to BOC (Side-Angle- Side)

<AOB = <BOC (In congruent triangles, corresponding elements are equal)

<ABO=<CBO

<AOB = <BOC

<ABO+<AOB =<CBO+<BOC

<ABO+<AOB=<DAB (In triangle, sum of two interior opposite angle equal to exterior angle)

<CBO+<BOC=< ECB(In triangle, sum of two interior opposite angle equal to exterior angle)

Therefore,

<DAB=<ECB