Question

Please help me out! I provided the questions below.

Answer 1

Question :

$\\(1) \pink\rm{\dfrac{3.8}{(4c+3)}=\dfrac{2}{2 \dfrac{ 2}{19}}}$

$\\ (2) \pink\rm{\dfrac{4.8}{1 \dfrac{7}{9} }=\dfrac{1.2b}{6 \dfrac{2}{3}}}$

To find :

(1) To find : The value of c

(2) To find : The value of b

Answer:

$\\ \blue \bigstar(1) \large\sf{ \dfrac{3.8}{(4c+3)}=\dfrac{2}{2 \dfrac{2}{9}}}$

$\\ \implies\sf{ \dfrac{3.8}{(4c+3)}=\dfrac{2}{2 \dfrac{2}{9}}}$

$\\ \large\implies\sf{ \dfrac{3.8}{(4c+3)}=\dfrac{2}{\dfrac{2 \times 9+2}{9}}}$

$\\ \large\implies\sf{ \dfrac{3.8}{(4c+3) } =\dfrac{2}{\dfrac{20}{9}}}$

$\\ \large\implies\sf{ \dfrac{3.8}{(4c+3) }=\dfrac{18}{20}}$

$\\ \large\implies\sf{\dfrac{3.8}{(4c+3)}=\dfrac{9}{10}}$

$\\ \large\implies\sf{3.8 \times 10=(4c+3)\times 9}$

$\\ \large\implies\sf{ 38=36c+27}$

$\\ \large\implies\sf{38-27=36c}$

$\\ \large\implies\sf{11=36c}$

$\\ \large\implies\sf{ c=\dfrac{11}{36}}$

$\\ \large\bigstar\boxed{\sf{c=\dfrac{11}{36}}}$

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$\blue\bigstar\large\sf{(2) \dfrac{4.8}{1 \dfrac{7}{9}} =\dfrac{1.2b}{6 \dfrac{2}{3}}}$

$\\ \implies\large\sf{\dfrac{4.8}{\dfrac{9+7}{9}}=\dfrac{1.2b}{\dfrac{6 \times 3 +2}{3}}}$

$\\ \implies\large\sf{\dfrac{43.2}{16}=\dfrac{3.6b}{20}}$

$\\ \implies\large\sf{\dfrac{10.8}{4}=\dfrac{1.8b}{10}}$

$\\ \implies\large\sf{\dfrac{5.4}{2}=\dfrac{0.9b}{5}}$

$\\ \implies\large\sf{2.7=\dfrac{0.9b}{5}}$

$\\ \implies\large\sf{2.7 \times 5 =0.9b}$

$\\ \implies\large\sf{13.5=0.9b}$

$\\ \implies\large\sf{b=135}{9}$

$\\ \implies\large\sf{b=15}$

$\qquad\large\bigstar\boxed{\sf{b=15}}$

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$\large\red\bigstar\boxed{\underline{\bf{the \: value \: of \: c \: =\dfrac{11}{36} \: \:and \: b=15}}}$