Math, asked by minzz1989, 3 months ago

please help me out if the answer would be correct l will mark it as brainliest. And if you write something nonsense I will report that question.​

Attachments:

Answers

Answered by univaryash
1

Answer:

Let the level of water be risen by 'h' cm

Then,

Volume of water in the tank =8000×2500×h

Area of cross-section of the pipe =25 cm2

Water coming out of the pipe forms a cuboid of base area 25 cm2 and length equal to the distance traveled in 45 minutes with the speed of 16 kmph

Length =16000×100×6045

Volume of water coming out of pipe in 45 minutes =25×16000×100(6045)

Now, Volume of water in the tank = Volume of water coming out of the pipe in 45 minutes

⇒8000×2500×h=16000×100×6045×25

⇒h=8000×2500×6016000×100×45×25

⇒h=1.5 cm

Answered by parthraina2005
1

Answer:

here is your answer please mark as brainliest.

Let the level of water be risen by 'h' cm

Then,

Volume of water in the tank =8000×2500×h

Area of cross-section of the pipe =25 cm

2

Water coming out of the pipe forms a cuboid of base area 25 cm

2

and length equal to the distance traveled in 45 minutes with the speed of 16 kmph

Length =16000×100×

60

45

Volume of water coming out of pipe in 45 minutes =25×16000×100(

60

45

)

Now, Volume of water in the tank = Volume of water coming out of the pipe in 45 minutes

⇒8000×2500×h=16000×100×

60

45

×25

⇒h=

8000×2500×60

16000×100×45×25

⇒h=1.5 cm

mark as brainliest

Similar questions