Question

Please help me out in this equation​

Answer 1

Answer:

$if \: given \: equation \: has \: solution \: then \: here \\ {b}^{2} - 4ac \: \geqslant 0 \\ {3}^{2} - 4t \times ( - 7) \geqslant 0 \\ 9 + 28t \geqslant 0 \\ 28t \geqslant - 9 \\ t \geqslant \frac{ - 9}{28} \\ \\ so \: here \: the \: value \: of \: t \: can \: be \: anything \: but \: greater \: than \: or \: eual \: to \: \frac{ - 9}{28}$