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Step-by-step explanation:
Taking L.H.S
Cos^2 A (1+tan^2 A)
1 +tan^2 A=sec^2 A
There for
Cos^2 A (1+tan^2 A)=cos^2 A (sec^2A)
Cos ^2 A × sec ^2 A =1 = R.H.S
L.H.S=R.H.S
HENCE PROVED
allu37:
(1+tan^2 A) Sin^2 A=tan^2 A
How to solve this
Cos 55 degree = sin 32 degree
How to show that?
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