Question

please help me out of this​

Answer 1

Answer:

hope this help uh.........

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ᴀɴsᴡᴇʀ࿐}}}$

+

2x

2

−5x+3

=

3

(x+1)

2

2x

2

−5x+3

=

3

(x+1)

2

−

2

3x−2

2x

2

−5x+3

=

6

2(x+1)

2

−3(3x−2)

6

2x

2

−5x+3

=2(x

2

+2x+1)−9x+6

6

2x

2

−5x+3

=2x

2

+4x+2−9x+6

6

2x

2

−5x+3

=2x

2

−5x+8

6

2x

2

−5x+3

=2x

2

−5x+3+5

6

2x

2

−5x+3

=(

2x

2

−5x+3

)

2

+5

Put

2x

2

−5x+3

=t, we get

6t=t

2

+5

t

2

−6t+5=0

t

2

−5t−t+5=0

t(t−5)−1(t−5)=0

(t−1)(t−5)=0

t=1,5

∴

2x

2

−5x+3

=t

2x

2

−5x+3=t

2

2x

2

−5x+3=1

2

...... [∵t=1]

2x

2

−5x+2=0.......(i)

2x

2

−4x−x+2=0

2x(x−2)−1(x−2)=0

(2x−1)(x−2)=0

x=

2

1

,2

Also 2x

2

−5x+3=5

2

2x

2

−5x−22=0.......(ii)

Using quadratic formula

x=

2(2)

5±

25−4(2)(−22)

=

4

5±

201

So the values of x are

4

5±

201

,

2

1

and 2