Question

❣️❣️Please help me out.❣️❣️


Solve the following pair of linear equation in two variable by cross multiplication method.
$\frac{x}{3} + \frac{y}{5} = 1$
and
$7x - 15y = 21$
​

Answer 1

Heya mate,

Here is your answer,. ⬇️⬇️

${ANSWER :-}$

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$<i>$ x/3 + y/5 = 1

=> ( 5x + 3y) = 15 *1 = 15

=> 3y = 15 - 5x

=> y = ( 15 - 5x)/3. ......... (1)

Now, we have,

7x - 15y = 21

=> 7x - 5(15 - 5x)/3 = 21 [ from (1) ]

=> 7x - 25 + 25x/3 = 21

=> 7x + 25x/3 = 21 + 25

=> 46x/3 = 46

=> x = 3 * 46 / 46 = 3. ⬅️

Now, 7 (3) - 15y = 21

=> 21 - 15y = 21

=> - 15y = 21 - 21 = 0

=> y = 0. ⬅️

➡️ Hence, x = 3 and y = 0.

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$<b>$ Hope this helps,.

If helps, please mark 'thanks'

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REGARDS, ARNAB ✌️

THANK YOU

Answer 2

very easy

the answer is (X,y)=(-3,0)

the soln is attached