Question

please help me out to solve this question of physics....?​

Answer 1

Answer:

a= [MLT ^-2 ] &

b=[MT ^-2 ]

Explanation:

By dimensional analysis we consider both the LHS and RHS have the same dimensions.

F=a+bx

In the given equation the LHS is F which stands for force

[F] = [MLT^-2 ]

now in RHS we have two constants a & b , by additive property we find that a and F will have the same dimension .

Thus [a] = [ MLT^ -2]

Now for…. bx , we know x is distance so it has dimension x= [ L ]

Thus we get bx = [ MLT ^-2]

=> b[ L ]= [ MLT ^-2]

=>. b= [ MT ^-2]

a= [MLT ^-2 ] & b=[MT ^-2 ]

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