Question

Please help me out with the fourth one .......!!

Answer 1

Hi...☺

Here is your answer...✌

GIVEN THAT,

Speed of an aircraft, S = 2.012×10³ km/h

We have to find distance covered in 3 h 30 min

Time , T = 3h 30 min

T = 3h + (1/2) h __[ ∵ 30 min = (1/2) h]

T = (3×2+1)/2 h

T = 7/2 h

Now,
We know that

Distance , D = S×T

D = 2.012 × 10³ × 7/2

D = 2.012×7/2 × 10³

D = 1.006×7 × 10³

D = 7.042 ×10³ km

HENCE,

The distance covered by aircraft in 3 hour 30 minutes is 7.042×10³

Answer 2

your answer is 7.042×10³ km

mark it as brainliest