Question

please help me out with this​

Answer 1

Answer:

Step-by-step explanation:

sec40=a/b

1/cos40=a/b

cos40=b/a

sin^2(40)+cos^2(40)=1

sin^2(40)=1-cos^2(40)

sin^2(40)=1-(b/a)^2

sin^2(40)=(a^2-b^2)/a^2

sin40=√(a^2-b^2)/a

sec50=sec(90-40)

=cosec40

=1/sin40

=1/√(a^2-b^2)/a

=a/(√a^2-b^2)