Question

Please Help Me Out With This.​

Answer 1

Answer:

angle POR=160 __ AS , it is a central angle , and

PQR =100 °

therefore, by using inscribed angle theorem,

m(arcPR) =2 m(anglePQR )

Then m(angle POR)= 360 -200 =160

BUT, POR forms a triangle , then

angles( OPR +POR +ORP) = 180° _ sum of all angles of a triangle is 180 __(1)

as PO=OR , radii of same circle,

angle OPR = angle ORP =x ( consideration). __(2)

therefore,

angle POR +x +x =180 ___from (1),(2),

POR =160

therefore , 160 +2x =180

2x =180 -160 = 20

therefore,

2x =20

x =10 ....

, angle OPR=ORP =10°

HOPE IT HELPS, PLS MARK AS BRAINLIEST

Answer 2

Answer:

hey mate... here is your answer

Step-by-step explanation:

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