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Consider, (1 – a2 – b2 – 2ab)
= [1 – (a2 + b2 + 2ab)]
= [12 – (a + b)2]
= [1 – (a + b)] [1 + (a + b)]
= [1 – a – b] [1 + a + b]
= [1 – (a2 + b2 + 2ab)]
= [12 – (a + b)2]
= [1 – (a + b)] [1 + (a + b)]
= [1 – a – b] [1 + a + b]
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