please help me out with this question
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2nd term: a+d=14......(1)
3rd term: a+2d=18...(2)
On solving 1 and 2 , we get
a=10 and d=4
Sum of 51 terms = n/2(2a+(n-1)d)
= 51/2(2×10+(51-1)4)
=5610 is the answer
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