Question

Please help me out with this question......I have the solution but dont know how to do....​

Answer 1

ANSWER:

let phi be x

secx + tanx=4

S.O.B.S

(sec x + tan x)^2= 4^2

sec^2x + tan^2x + 2secxtanx=16

1 + 2sinx/cos^2x=16

2sinx/cos^2x=15

2sinx=15(cos^2x)

2sinx=15(1-sin^2x)

15sin^2x + 2sinx - 15 = 0

therefore, sin x=15/17 and cosx=8/17

I got only till there after that I'm unable to solve.

SORRY

Answer 2

Step-by-step explanation:

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