Question

please help me please......

Answer 1

if a+b+c=0 then a^3+b^3+c^3 = 3abc

= 3(a^2-b^2)+ (b^2-c^2) + (c^2-a^2)/3(a+b) + (b+c) + (c+a)

= 3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)/3(a+b)(b+c)(c+a)

= (a-b)(b-c)(c-a)