Question

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Answer 1

Step-by-step explanation:

i) area of the triangular flower bed is

1/2×3.5×2 sq m

=3.5 sq m

area of the square flower bed is( 2.5)^2sq m

=6.25 sq m

so,square flower bed has more area than triangular flower bed.

ii) area of the circular flower bed

=π(2.1/2)^2 sq m

=22/7(1.05)^2 sq m

=22×1.05×1.05/7 sq m

=22×1.05×.15 sq m

=3.465 sq m

area of the trapezium flower bed

=(2+3)/2×1.5 sq m

=5×1.5/2 sq m

=2.5×1.5 sq m

=3.75 sq m

circular flower bed has least area

iii) perimeter of the vidyalaya park is

2(55+42) m

=2×97 m

=194 m

iv) cost of planting jesmine flower in circular bed is Rs 3.465×8

= Rs 27.72

Answer 2

Answer:

i) area of the triangular flower bed is

1/2×3.5×2 sq m  

=3.5 sq m  

area of the square flower bed is( 2.5)^2sq m  

=6.25 sq m  

so,square flower bed has more area than triangular flower bed.  

ii) area of the circular flower bed  

=π(2.1/2)^2 sq m  

=22/7(1.05)^2 sq m  

=22×1.05×1.05/7 sq m  

=22×1.05×.15 sq m  

=3.465 sq m  

area of the trapezium flower bed  

=(2+3)/2×1.5 sq m  

=5×1.5/2 sq m  

=2.5×1.5 sq m  

=3.75 sq m  

circular flower bed has least area

iii) perimeter of the vidyalaya park is  

2(55+42) m  

=2×97 m  

=194 m  

iv) cost of planting jesmine flower in circular bed is Rs 3.465×8  

= Rs 27.72

Step-by-step explanation:

Thanks..