Question

please help me please​

Answer 1

We are given that the metal Y is reddish brown in colour. This metal is copper. The blue solution is Copper Sulphate solution.

Also, zinc is used in protecting iron articles (process called galvanisation). Zinc is more reactive than copper and hence can displace copper from its salt solution. So when substance X is added, Zinc displaces copper to form Zinc Sulphate solution which is colourless. Hence the colour of the solution gets discharged.

X + Blue solution ---> Y + Colourless solution

ie,

Zn(s) + CuSO4(aq) ---> Cu(s)+ ZnSO4(aq)

So, X is Zinc, while Y is Copper. The reaction is a Displacement reaction.

In the presence of air all metals with exception of the precious metals oxidize. The most familiar reaction of this type is the rusting of iron. Rusting is deleterious because the iron oxide flakes off exposing more surface for continued oxidation. With many metals, the oxide forms a thin layer on the surface of the metal that adheres tightly to it. This means that an oxide coating on these metals is actually protective.

Lead (II) Nitrate: PbNO3

Potassium Oxide : KI 1)

I)Colour of Precipitate : Yellow

II) Name of Precipitate: Lead lodide

III) Equation: PbNO3+Kl---->Pbl2 (Precipitate ate)

(Yellow)KNO3

IV) It's a double displacement ----> Precipitation Reaction,as, Both of the ions are being exchanged

Zn+H 2 SO 4 longrightarrow ZnSO 4 +H 2 ↑

(+) We can observe bubbles of H2 gas being formed around zinc granules.

(+) This is an exothermic reaction, i.e. it involves release heat and the flask become hot and temperature of the system increases.

(+) The glass tube is not dipped in the solution so as to collect enough, H2 gas. It is was dipped in H2 SO4 solution would enter the tube presenting H_{2} gas to enter the tube.

(+) H2 gas is collected by downward displacement of water.

(+) H2 gas is insoluble in water.

(+) H2 gas is lighter than air.